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CCSS Math Answers

Eureka Math Grade 5 Module 5 Lesson 13 Answer Key

Engage ny eureka math 5th grade module 5 lesson 13 answer key, eureka math grade 5 module 5 lesson 13 problem set answer key.

Question 1. Find the area of the following rectangles. Draw an area model if it helps you. a. \(\frac{5}{4}\) km × \(\frac{12}{5}\) km b. 16\(\frac{1}{2}\) m × 4\(\frac{1}{5}\) m c. 4\(\frac{1}{3}\) yd × 5\(\frac{2}{3}\) yd d. \(\frac{7}{8}\) mi × 4\(\frac{1}{3}\) mi Answer:

Therefore, 3 square kilometres

16 1/2 x 4 1/5

=  (16 x 4) + ( 16 x 1/5) + ( 4 x 1/2) x ( 1/2 x 1/5 )

= 64 + 16/5 + 2 + 1/10

Therefore, 69 3/10 square metres

4 1/3 x 5 2/3

4 x 5 + 4 x 2/3 + 5 x 1/3 + 1/3 x 2/3

= 20 +8/3 +5/3 +2/9

Therefore, 24 5/9 square yards

d.7/8 mi x 4 1/3 mi

= (7/8 x 4) + (7/8 x 1/3)

= 84/24 + 7/24

Therefore, 3 19/24 sq. mi

Question 2. Julie is cutting rectangles out of fabric to make a quilt. If the rectangles are 2\(\frac{3}{5}\) inches wide and 3\(\frac{2}{3}\) inches long, what is the area of four such rectangles? Answer:

Given, the measurements of the rectangles =

2 3/5 x 3 2/3

=( 2 x 3 ) + (2 x 2/3) + (3 x 3/5) + ( 3/5 x 2/3)

= 6 + 4/3 + 9/5 + 6/15

=6 + 3 8/15

= 9 8/15 square inches

Now, number of rectangles = 4

So, 4 x 9 8/15

= 36 + 2 2/15

Therefore, 38 2/15 square inches.

Engage NY Math Grade 5 Module 5 Lesson 13 Problem Set Answer Key 1

Given, the measurements of the lawn = 24 1/2 yd by 24 1/2 yd

The area of the lawn =

24 1/2 x 24 1/2

= (24 x 24 ) + (24 x 1/2 ) + (24 x 1/2) + ( 1/2 x 1/2)

= 576 + 12 +12 +1/4

=600 1/4 square yards

The area of the pool house = 16 square yards

The area of the pool =

7 1/2 yd x 2 1/2 yd

= 14 + 3 1/2 + 1 + 1/4

The area of sidewalk = 1 yd x 3 yd = 3 yd

Now, the amount of sod Howard needs to buy =

6001/4 – 16 – 18 3/4 – 3

= 581 1/4 – 18 2/4

= 580 5/4 – 18 3/4

= 562 1/2 square yards

Therefore, Howard need 562 1/2 square yards of sod.

Eureka Math Grade 5 Module 5 Lesson 13 Exit Ticket Answer Key

Find the area of the following rectangles. Draw an area model if it helps you. Question 1. \(\frac{7}{2}\) mm × \(\frac{14}{5}\) mm Answer:

7/2 mm x 4/5 mm

= 7/2 x 4/5

= 9 4/5 square mm

Question 2. 5\(\frac{7}{8}\) km × \(\frac{18}{4}\) km Answer:

5/8 km x 18/4 km

= 5/8 x 18/4

= 26 7/16 square kilometres.

Eureka Math Grade 5 Module 5 Lesson 13 Homework Answer Key

Question 1. Find the area of the following rectangles. Draw an area model if it helps you. a. \(\frac{8}{3}\) cm × \(\frac{24}{4}\) cm b. \(\frac{32}{5}\) ft × 3\(\frac{3}{8}\) ft c. 5\(\frac{4}{6}\) in × 4 \(\frac{3}{5}\) in d. \(\frac{5}{7}\) m × 6\(\frac{3}{5}\) m Answer:

8/3 cm x 24/4 cm

= 8/3 x 24/4

Therefore, 16 square centimetres

32/5 feet x 3 3/8

32/5 = 6 2/5

= 18 +  18/8 + 6/5 + 9/40

=  18 + 2 1/4 + 1 1/5 + 9/40

= 21 + 27/40

Therefore, 21 27/40 square feet

5 4/6 feet x 4 3/5 feet

( 5 x 4 ) + ( 5 x 3/5) + (4/6 x 4 ) + ( 4/6 x 3/5)

= 20 + 15/5 + 16/6 + 12/30

=20 + 3 + 8/3 + 2/5

= 25 +20/30 + 12/30

Therefore, 26 1/15 square inches

5/7 m x 6 3/5 m

= 5/7 x 6 3/5

=  30/7 + 15/35

= 4 2/7 + 3/7

Therefore, 4 5/7 square inches

Question 2. Chris is making a tabletop from some leftover tiles. He has 9 tiles that measure 3\(\frac{1}{8}\) inches long and 2\(\frac{3}{4}\) inches wide. What is the greatest area he can cover with these tiles? Answer:

Given, the measurements of the tiles =

3 1/8 x 2 3/4

= 6 + 9/4 + 2/8 + 3/32

= 6 +2 1/4 + 1/4 + 3/32

Now, the greatest area he can cover with 9 tiles=

= 9 x 8 19/32

= 72 + 191/32

= 72 +5 11/32

= 77 11/32 square inches.

Therefore, the greatest area he can cover = 77 11/32.

Eureka Math Grade 5 Module 5 Lesson 13 Homework Answer Key 1

31 7/8 x 19 1/2

= ( 31 x 19) + ( 31 x 1/2 ) + (19 x 7/8 ) + ( 7/8 x 1/2)

= 589 + 31/2 + 133/8 + 7/16

= 589 + 15 1/2 + 16 5/8 + 7/16

= 620 + 1/2 + 5/8 + 7/16

= 630 + 8/16 + 10/16 + 7/16

= 620 25/16 square feet.

b. 13 3/5 feet x 11 3/4 feet

= ( 13 x 11) + ( 13 x 3/4 ) + (3/5 x 11 ) + ( 3/5 x 3/4)

= 143 + 9 3/4 + 6 3/5 + 9/20

=158 + 15/20 + 12/20 + 9/20

= 159 16/20

= 159 4/5 square feet

= 36 + 36/4

= 45 square feet

= 34 + 17/2

= 34 + 8 1/2

= 42 1/2 square feet

159 4/5 + 45 + 42 1/2

= 247 3/10 square feet

So, 621 9/16 – 247 3/10

= 384 21/80

Therefore, 384 21/80 square feet of carpeting is needed.

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Unit 10: Area

About this unit, area introduction.

  • No videos or articles available in this lesson
  • Understand area Get 3 of 4 questions to level up!

Count unit squares to find area

  • Intro to area and unit squares (Opens a modal)
  • Measuring rectangles with different unit squares (Opens a modal)
  • Creating rectangles with a given area 1 (Opens a modal)
  • Creating rectangles with a given area 2 (Opens a modal)
  • Find area by counting unit squares Get 5 of 7 questions to level up!
  • Compare area with unit squares Get 5 of 7 questions to level up!
  • Create rectangles with a given area Get 3 of 4 questions to level up!

Area formula intuition

  • Counting unit squares to find area formula (Opens a modal)
  • Transitioning from unit squares to area formula (Opens a modal)
  • Area with partial grids (Opens a modal)
  • Area of rectangles with partial arrays Get 5 of 7 questions to level up!
  • Transition from unit squares to area formula Get 5 of 7 questions to level up!

Multiply to find area

  • Finding missing side when given area (Opens a modal)
  • Comparing areas of plots of land (Opens a modal)
  • Area of rectangles review (Opens a modal)
  • Area of rectangles Get 5 of 7 questions to level up!
  • Find a missing side length when given area Get 5 of 7 questions to level up!
  • Compare areas by multiplying Get 3 of 4 questions to level up!

Area and the distributive property

  • Area and the distributive property (Opens a modal)
  • Area and the distributive property Get 3 of 4 questions to level up!

Decompose figures to find area

  • Decomposing shapes to find area: grids (Opens a modal)
  • Decomposing shapes to find area: add (Opens a modal)
  • Decomposing shapes to find area: subtract (Opens a modal)
  • Area: FAQ (Opens a modal)
  • Understand decomposing figures to find area Get 3 of 4 questions to level up!
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Go Math Answer Key

Texas Go Math Grade 5 Lesson 13.5 Answer Key Multi-Step Measurement Problems

Refer to our Texas Go Math Grade 5 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 5 Lesson 13.5 Answer Key Multi-Step Measurement Problems.

Essential Question How can you solve multi-step problems that include measurement conversions? Answer: The steps to solve the multi-step problems that include measurement conversions are: Step 1: Write the given information and what to find Step 2: Plan a strategy how to find the required information or quantity Step 3: If there are unit conversions, then convert them by using the following rules: If we have to convert a small unit into a larger unit, then multiply If we have to convert a larger unit into a small unit, then divide

Unlock the Problem

A leaky faucet in Jarod’s house drips 2 cups of water each day. After 2 weeks of dripping, the faucet is fixed. ¡fit dripped the same amount each day, how many quarts of water dripped from Jarod’s leaky faucet in 2 weeks?

Use the steps to solve the multi-step problem. Step 1 Record the information you are given. The faucet drips 2 cups of water each day. The faucet drips for 2 weeks.

lesson 13 5 problem solving find the area

Step 3 Convert from cups to quarts. Think: There are 2 cups in 1 pint. There are 2 pints in 1 quart. 2 cups = 2 pints 2 pints = 4 quarts So, Jarod’s leaky faucet drips 56 quarts of water in 2 weeks.

• What if the faucet dripped for 4 weeks before it was fixed? How many quarts of water would have leaked? Answer: From the above Problem, We can observe that Jarod’s leaky faucet drips 56 quarts of water in 2 weeks. So, The number of quarts of water if the faucet dripped for 4 weeks = 2 × (The number of quarts of water if the faucet dripped for 2 weeks) = 2 × 56 = 112 quarts Hence, from the above, We can conclude that The number of quarts of water if the faucet dripped for 4 weeks is: 112 quarts of water

Example A carton of large, Grade A eggs weighs about 1.5 pounds. If a carton holds a dozen eggs, how many ounces does each egg weigh?

Texas Go Math Grade 5 Lesson 13.5 Answer Key 9

So, Each egg weighs about 2 ounces.

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Question 1. After each soccer practice, Scott runs 4 sprints of 20 yards each. If he continues his routine, how many practices will it take for Scott to have sprinted a total of 2 miles combined? Scott sprints ___ yards each practice. Since there are ___ yards in 2 miles, he will need to continue his routine for ___ practices. Answer: It is given that After each soccer practice, Scott runs 4 sprints of 20 yards each. So, The number of yards Scott sprints each practice = 4 × 20 = 80 yards Now, We know that, 1 mile = 1,760 yards So, The number of practices will it take for Scott to have sprinted a total of 2 miles = \(\frac{2 × 1,760}{80}\) = 44 practices Hence, from the above, We can conclude that The number of practices will it take for Scott to have sprinted a total of 2 miles is: 44 practices

Go Math Answer Key Grade 5 Step Measurement Question 2. A worker at a mill is loading 5-lb bags of flour into boxes to deliver to a local warehouse. Each box holds 12 bags of flour. If the warehouse orders 3 tons of flour, how many boxes are needed to fulfill the order? Answer: It is given that A worker at a mill is loading 5-lb bags of flour into boxes to deliver to a local warehouse. Each box holds 12 bags of flour Now, According to the given information, The total number of bags of flour = (The total number of bags) × 5 = 5 × 12 = 60 bags of flour Now, We know that, 1 Ton = 2,000 Pounds So, The total number of boxes needed to fulfill the given order = (The total quantity of the order) ÷ (The number of bags of flour) = \(\frac{3 × 2,000}{60}\) = \(\frac{6,000}{60}\) = 100 boxes Hence, from the above, We can conclude that The total number of boxes needed to fulfill the given order is: 100 boxes

Question 3. Cory brings five 1-gallon jugs of juice to serve during parent night at his school. If the paper cups he is using for drinks can hold 8 fluid ounces, how many drinks can Cory serve for parent night? Answer: It is given that Cory brings five 1-gallon jugs of juice to serve during parent night at his school Now, We know that, 1 Gallon = 4 Quarts 1 Quart = 2 Pints 1 Pint = 2 cups 1 cup = 8 fluid ounces So, 1 Gallon = 4 × 2 × 2 × 8 = 8 × 16 = 128 fluid ounces Now, The number of drinks that Cory can serve for Parent night = \(\frac{128}{8}\) = 16 drinks Hence, from the above, We can conclude that The number of drinks that Cory can serve for Parent night is: 16 drinks

Math Talk Mathematical Processes Explain the steps you took to solve Exercise 2? Answer: The steps that you took to solve Exercise 2 are: Step 1: Find the number of bags of flour Step 2: Convert 3 tons into pounds Step 3: Divide the result in Step 3 and the result in Step 2 respectively to find the number of boxes that are needed to fulfill the order

Problem Solving

Question 4. Apply A science teacher needs to collect lake water for a lab she is teaching about purifying water. The lab requires each student to use 4 fluid ounces of lake water. If 68 students are participating, how many pints of lake water will the teacher need to collect? Answer: It is given that A science teacher needs to collect lake water for a lab she is teaching about purifying water. The lab requires each student to use 4 fluid ounces of lake water Now, We know that, 1 cup = 8 fluid ounces 1 pint = 2 cups So, 4 fluid ounces = \(\frac{1}{4}\) pint So, According to the given information, The number of pints of lake water the teacher will be needed to collect  = 68 × 4 fluid ounce = 272 fluid ounces = \(\frac{272}{16}\) = 17 pints Hence, from the above, We can conclude that The number of pints of lake water the teacher will need to collect is: 17 pints

Go Math Grade 5 Multiple-Step Problems Answer Key Question 5. H.O.T. Use Diagrams A string of decorative lights is 28 feet long. The first light on the string is 16 inches from the plug. If the lights on the string are spaced 4 inches apart, how many lights are there on the string? Draw a picture to help you solve the problem. Answer: It is given that A string of decorative lights is 28 feet long. The first light on the string is 16 inches from the plug and the lights on the string are spaced 4 inches apart Now, We know that, 1 feet = 12 inches So, The total length of a string = 28 × 12 = 336 inches Now, The remaining length of the string = (The total length of the string) – (The distance of the first light on the string) = 336 – 16 = 320 inches So, The total number of lights that are present on the string = (The remaining length of the string) ÷ (The distance of each light placed) = \(\frac{320}{4}\) = 80 lights Hence, from the above, We can conclude that The total number of lights that are present on the string is: 80 lights

Question 6. Multi-Step When Jamie’s car moves forward such that each tire makes one full rotation, the car has traveled 72 inches. How many full rotations do the tires make when Jamie’s car travels 10 yards? Answer: It is given that When Jamie’s car moves forward such that each tire makes one full rotation, the car has traveled 72 inches Now, The distance travelled in one rotation = 72 inches, So, The number of rotation the car travelled for 72 inches = 1 Now, The number of rotations the car travelled for 1 inches= \(\frac{1}{72}\) Also, It is given that The car travelled 10 yards Now, We know that, 1 yard = 36 inches So, The distance travelled by the car = 36 × 10 = 360 inches So, The number of rotations the car travelled for 360 inches = \(\frac{360}{72}\) = 5 rotations Hence, from the above, We can conclude that The number of rotations the car travelled for 360 inches is: 5 rotations

Question 7. Multi-Step A male African elephant weighs 7 tons. If a male African lion at the local zoo weighs 13,650 pounds less than the male African elephant, how many pounds does the lion weigh? Answer: It is given that A male African elephant weighs 7 tons and a male African lion at the local zoo weighs 13,650 pounds less than the male African elephant Now, We know that, 1 Ton = 2,000 pounds So, The weight of a male African elephant = 7 × 2,000 pounds = 14,000 pounds Now, According to the given information, The weight of a male African lion = 14,000 – 13,650 = 350 Pounds Hence, from the above, We can conclude that The weight of a male African elephant is: 350 pounds

Question 8. Multi-Step An office supply company is shipping a case of pencils to a store. There are 64 boxes of pencils in the case. If each box of pencils weighs 2.5 ounces, what is the weight, in pounds, of the case of pencils? Answer: It is given that An office supply company is shipping a case of pencils to a store. There are 64 boxes of pencils in the case. If each box of pencils weighs 2.5 ounces So, The total weight of the case of pencils = 64 × (The weight of each box of pencils) = 64 × 2.5 = 160 ounces Now, We know that, 1 pound = 16 ounces 1 ounce = \(\frac{1}{16}\) pounds So, The total weight of the case of pencils in pounds = 160 × \(\frac{1}{16}\) = 10 pounds Hence, from the above, We can conclude that The total weight of the case of pencils in pounds is: 10 pounds

Texas Go Math Grade 5 Lesson 13.5 Answer Key 12

Daily Assessment Task

Fill in the bubble completely to show your answer.

lesson 13 5 problem solving find the area

Texas Test Prep

lesson 13 5 problem solving find the area

Texas Go Math Grade 5 Lesson 13.5 Homework and Practice Answer Key

Question 1. Diego drinks 16 ounces of his favorite sport drink every day after soccer practice for 2 weeks. How many quarts of the sport drink does Diego consume in 2 weeks? Answer: It is given that Diego drinks 16 ounces of his favorite sport drink every day after soccer practice for 2 weeks Now, We know that, 1 cup = 8 fluid ounces 1 pint = 2 cups 1 quart = 2 pints 1 week = 7 days 1 quart = 32 ounces So, The number of quarts of the sport drink does Diego consume in 2 weeks = 2 × 7 ×  \(\frac{16}{32}\) = 14 × \(\frac{1}{2}\) = 7 quarts Hence, from the above, We can conclude that The number of quarts of the sport drink does Diego consume in 2 weeks is: 7 quarts

Question 2. A rancher is putting a fence around a square animal pen. The perimeter of the pen is 32 feet. The fence posts will be 16 inches apart. She starts by putting 1 fence post at each corner of the pen. How many fence posts does she use altogether? Draw a picture to model the problem. Answer: It is given that A rancher is putting a fence around a square animal pen. The perimeter of the pen is 32 feet. The fence posts will be 16 inches apart. She starts by putting 1 fence post at each corner of the pen Now, We know that, 1 feet = 12 inches So, The perimeter of the pen = 32 × 12 = 384 inches So, The number of fence posts does a rancher used altogether = \(\frac{384}{16}\) = 24 fence posts Hence, from the above, We can conclude that The number of fence posts a rancher uses altogether is: 24 fence posts

5th Grade Go Math Answer Key Lesson 13.5 Question 3. A koala weighs 20 pounds. In her pouch, she carries her joey which weighs 20 ounces. What is the combined weight of the adult koala and her joey in ounces? Answer: It is given that A koala weighs 20 pounds. In her pouch, she carries her Joey which weighs 20 ounces Now, We know that, 1 pound = 16 ounces So, The combined weight of the adult koala and her joey in ounces = (20 × 16) + 20 = 320 + 20 = 340 ounces Hence, from the above, We can conclude that The combined weight of the adult koala and her joey in ounces is: 340 ounces

Question 4. On Friday, 32 students in Mr. Tanika’s class are each served 6 ounces of milk for lunch. How many quarts of milk are served to the class on Friday? Answer: It is given that On Friday, 32 students in Mr. Tanika’s class are each served 6 ounces of milk for lunch Now, We know that, 1 quart = 32 ounces So, The number of quarts of milk are served to the class on Friday = 32 × 6 ounces = 192 ounces = \(\frac{192}{32}\) = 6 quarts Hence, from the above, We can conclude that The number of quarts of milk are served to the class on Friday is: 6 quarts

Question 5. Vanessa bought 5 feet of ribbon. She cut off 36 inches to wrap a package and 18 inches to decorate her scrapbook. How much ribbon does Vanessa have left? Answer: It is given that Vanessa bought 5 feet of ribbon. She cut off 36 inches to wrap a package and 18 inches to decorate her scrapbook Now, We know that, 1 feet = 12 inches So, According to the given information, The amount of ribbon does Vanessa has left = (5 × 12) – (36 + 18) = 60 – 54 = 6 inches Hence, from the above, We can conclude that The amount of ribbon does Vanessa has left is: 6 inches

Question 6. Students fill beanbags to play a classroom number game. Each beanbag contains 3 cups of beans. They have a 1-pint container, a 1-quart container, and a 1-gallon container filled with beans to use for the beanbags. What is the greatest number of beanbags they can make? Answer: It is given that Students fill beanbags to play a classroom number game. Each beanbag contains 3 cups of beans. They have a 1-pint container, a 1-quart container, and a 1-gallon container filled with beans to use for the beanbags Now, We know that, 1 pint = 2 cups 1 quart = 2 pints 1 gallon = 4 quarts So, The number of beanbags present in a 1-pint container = 3 × 2 = 6 beanbags The number of beanbags present in a 1-quart container = 3 × 2 × 6 = 36 beanbags The number of beanbags present in a 1-gallon container = 3 × 4 × 36 = 432 beanbags Hence, from the above, We can conclude that The greatest number of beanbags the students can make is: 432 beanbags

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Estimating Length

Kg -  2nd  , area and perimeter, 9th -  10th  , measurement.

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Go Math 13.5 - Problem Solving: Find the...

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Go Math 13.5 - Problem Solving: Find the Area

lesson 13 5 problem solving find the area

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Page 745 #1

40 square feet

96 square feet

20 square feet

75 square feet

Page 745 #2

4 square feet

79 square feet

71 square feet

Page 745 #3

Page 746 #4

How much does the CAT weigh?

How much does the DOG weigh?

Page 746 #5

Page 746 #6

Page 747 #2

112 square feet

128 square feet

60 square feet

Page 747 #3

280 square yards

235 square feet

45 square feet

235 square yards

Page 747 #4

192 square feet

192 square inches

192 square yards

672 square inches

Page 748 #1

34 square inches

34 square feet

46 square feet

Page 748 #2

81 square yards

90 square feet

99 square feet

81 square feet

Page 748 #3

Page 748 #4

Mary and Terry

Page 748 #5

21, 23, 27, 29

Page 748 #6

1 hour 45 minutes

2 hours 15 minutes

1 hour 30 minutes

2 hours 45 minutes

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Area and Perimeter

This SMILE resource contains three packs of games, investigations, worksheets and practical activities supporting the teaching and learning of area and perimeter, from calculating area by counting squares to finding the formula for the area of a trapezium.

Area and Perimeter pack one  contains fourteen work cards with a wide variety of activities covering finding areas by counting squares, finding the length of perimeters by counting, developing the formula for the area of a rectangle, drawing different shapes with a given perimeter, finding different shapes with a given area and finding the area of simple compound shapes.

Area and Perimeter pack two  contains eleven work cards with activities requiring students to make shapes of a given size using pentominoes, investigate the area and perimeter of rectangles, find the area of a right-angled triangle, calculate the area of polygons drawn on square dotted paper, investigate different ways of shading half a square, find the area of a triangle, find the area of compound shapes made from rectangles and find the area of a parallelogram.

Area and Perimeter pack three  contains eleven work cards with activities in which students investigate the connections between the area of a parallelogram and the area of a rectangle, the area of obtuse-angled triangles, further parallelogram problems, finding the area of a polygon, finding the area of a trapezium and calculating the area of irregular shapes.

SMILE (Secondary Mathematics Individualised Learning Experiment) was initially developed as a series of practical activities for secondary school students by practising teachers in the 1970s. It became a complete individualised scheme based around a network of activity cards and assessments. Related resources include answers  to all of the cards and test books and answers .

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  1. Problem Solving

    Here we find the area of two rectangles, then subtract to get our answer.

  2. PDF Name Lesson 13.5 Problem Solving • Find the Area

    First, find the area of the playground. I need to find how many ___ the landscaper will use. What information do I need to use? The grass will cover the ___. A b × h _ _ = × square yards _ = Next, find the area of the sandbox. The grass will not cover the ___. The length and width of the playground are ___ and ___.

  3. 4th grade GO Math-Lesson 13.5 Problem Solving-Find the Area pages 543

    This video covers Lesson 13.5 Problem Solving-Find the Area on pages 543-546 of the 4th grade GO Math textbook. Show more Try YouTube Kids Learn more David Hammond 4th grade GO...

  4. Go Math 13.5 Find the Area

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  5. Eureka Math Grade 5 Module 5 Lesson 13 Answer Key

    Find the area of the following rectangles. Draw an area model if it helps you. a. 54 km × 125 km b. 16 12 m × 4 15 m c. 4 13 yd × 5 23 yd d. 78 mi × 4 13 mi Answer: a. 5/4 x 12/5 = 60/20 = 3 Therefore, 3 square kilometres b. 16 1/2 x 4 1/5 = (16 x 4) + ( 16 x 1/5) + ( 4 x 1/2) x ( 1/2 x 1/5 ) = 64 + 16/5 + 2 + 1/10 = 66 33/10 = 66 3/10

  6. PDF Practice and Homework Name Lesson 13.5 Problem Solving • Find the Area

    13.5 COMMON CORE STANDARD—4.MD.A.3 Solve problems involving measurement and conversion of measurements from a larger unit to a smaller unit. 10 ft 6 ft 8 ft Area of the floor: 13 10 130 square feet 13 ft = Area of the rug: 8 6 48 square feet × = Subtract to find the area of the floor still showing: 130 48 82 square feet − = 2.

  7. Lesson 13.5- Finding Area Flashcards

    Start studying Lesson 13.5- Finding Area. Learn vocabulary, terms, and more with flashcards, games, and other study tools. ... Spell. Test. PLAY. Match. Gravity. Created by. BWilson_School9. Terms in this set (3) How do you find the area of a multi-step problem. Ned wants to wallpaper the wall of his bedroom that has a door. The wall is 14 feet ...

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    Objective: Lesson 13.5 Problem Solving Find the Area (MACC.4.MD.1.3) ... Problem Solving: Find the Area We know how to find the area of a rectangle, but shapes that we want the area of aren't always rectangles! How co Ind the area of this rectangular donut pi Thngs to . Title:

  9. PDF Problem Solving • Find the Area

    the area of the wall. Problem Solving • Find the Area Use the strategy solve a simpler problem. Marilyn is going to paint a wall in her bedroom. The wall is 15 feet long and 8 feet tall. The window takes up an area 6 feet long and 4 feet high. How many square feet of the wall will Marilyn have to paint? Lesson 13.5 Reteach Chapter Resources ...

  10. Go Math Grade 4 Answer Key Homework Practice FL Chapter 13: Algebra

    Lesson: 5 - Problem Solving Find the Area. Common Core - Algebra: Perimeter and Area - Page No. 255; ... Lesson 13.5. Solve. Question 5. Jeanette is painting a rectangular wall that is 10 feet long and 8 feet tall. There is a window that is 5 feet wide and 3 feet tall on the wall. What is the area of the wall that Jeannette will paint?

  11. 4th Grade

    About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features NFL Sunday Ticket Press Copyright ...

  12. PDF Area of Polygons 13-4 Reteach

    Sometimes you can use area formulas you know to help you find the area of more complex figures. You can break a polygon into shapes that you know. Then use those shapes to find ... LESSON 13-4 Practice and Problem Solving: A/B 1. 5 in2 2. 7 cm2 3. 12 ft2 4. 6 m2 5. 24 yd2 6. 17 mi2 7. 109,600 mi2 8. 63,800 mi2 Practice and Problem Solving: C 1 ...

  13. PDF A Problem Solving Approach to Mathematics for Elementary School

    A square field has a side of 400 m. Find the area of the field in hectares. 400 m 160,000 m ha 16ha 2 2 160,000 10,000 A b. A square field has a side of 400 yd. Find the area of the field in acres. 400yd 160,000yd 2 2 160,000 acre 33.1 acres 4840 A |

  14. 6th grade (Illustrative Mathematics)

    Unit 6: Expressions and equations. 0/3000 Mastery points. Lesson 1: Tape diagrams and equations Lesson 2: Truth and equations Lesson 3: Staying in balance Lesson 4: Practice solving equations and representing situations with equations Lesson 5: A new way to interpret a over b Extra practice: Equations Lesson 6: Write expressions where letters ...

  15. Area

    3rd grade 14 units · 141 skills. Unit 1 Intro to multiplication. Unit 2 1-digit multiplication. Unit 3 Addition, subtraction, and estimation. Unit 4 Intro to division. Unit 5 Understand fractions. Unit 6 Equivalent fractions and comparing fractions. Unit 7 More with multiplication and division. Unit 8 Arithmetic patterns and problem solving.

  16. PDF Area of Triangles 13-2 Practice and Problem Solving: A/B

    Solve. 5. The front part of a tent is 8 feet long and 5 feet tall. What is the area of the front part of the tent? _____ 6. Kathy is playing a board game. The game pieces are each in the shape of a triangle. Each triangle has a base of 1.5 inches and a height of 2 inches. ... LESSON 13-2 . Title:

  17. Texas Go Math Grade 5 Lesson 13.5 Answer Key Multi-Step Measurement

    Answer: The steps to solve the multi-step problems that include measurement conversions are: Step 1: Write the given information and what to find Step 2: Plan a strategy how to find the required information or quantity Step 3: If there are unit conversions, then convert them by using the following rules:

  18. PDF Solving Area Equations 13-3 Practice and Problem Solving: A/B

    of the house is 20 feet. The area of the front of the A-frame is 600 square feet. Write and solve an equation to find the base of the A-frame house. _____ 2. A countertop is in the shape of a trapezoid. The lengths of the bases are 70 1 2 and 65 1 2 inches long. The area of the countertop is 1,224 square inches. Write and solve an equation to ...

  19. Go Math 13.5

    Go Math 13.5 - Problem Solving: Find the Area 0 plays 4th grade Mathematics 16 minutes ago by Danielle Barter INSTRUCTOR-LED SESSION Start a live quiz ASYNCHRONOUS LEARNING Assign homework 16 questions Question 1 30 seconds Report an issue Q. Page 745 #1 answer choices 40 square feet 96 square feet 20 square feet 75 square feet Question 2

  20. Go Math: 13.5 Problem-Solving Find the Area

    Go Math: 13.5 Problem-Solving Find the Area Allison Spears 155 subscribers 911 views 3 years ago This is a walkthrough of the lesson questions for pages 743-746. Show more Try...

  21. Area and Perimeter

    This SMILE resource contains three packs of games, investigations, worksheets and practical activities supporting the teaching and learning of area and perimeter, from calculating area by counting squares to finding the formula for the area of a trapezium. Area and Perimeter pack one contains fourteen work cards with a wide variety of activities covering finding areas by counting squares ...

  22. PDF What's My Area? Geometry and Problem Solving

    problems involving angle, measure, area, surface area, and volume (CCR.MA.ABE.4.4.2) solve angle, measure, area, surface area, volume problems DOK 2 Objectives of the Lesson Students will: Use geoboards to pictorially display geometric concepts Define a polygon Draft solutions to problems regarding area and perimeter using geoboards or dot paper

  23. PDF A Problem Solving Approach to Mathematics for Elementary School

    How does the surface area of a sphere 10 in. in diameter compare with the surface area of a sphere 5 in. in diameter? Any two spheres are similar. The ratios of the diameters is 10:5 or 2. Ratio of surface areas is 22 or 4. The 10-in sphere has 4 times the surface area of the 5-inch sphere.